wake-up-neo.com

Return-Index eines Elements in einem Array-Excel-VBA

Ich habe ein Array PrLst, das eine Liste von Ganzzahlen ist. Die Ganzzahlen werden nicht sortiert, da ihre Position im Array eine bestimmte Spalte in einer Kalkulationstabelle darstellt. Ich möchte wissen, wie ich eine bestimmte Ganzzahl im Array finde und seinen Index zurückließe. 

Es scheint keine Ressource zu geben, die mir zeigt, wie das Array in einen Bereich im Arbeitsblatt umgewandelt wird. Das erscheint etwas kompliziert. Ist das mit VBA einfach nicht möglich?

arraysexcelvbaindexingfind
47
H3lue
Dim pos, arr, val

arr=Array(1,2,4,5)
val = 4

pos=Application.Match(val, arr, False)

if not iserror(pos) then
   Msgbox val & " is at position " & pos
else
   Msgbox val & " not found!"
end if

Die Anzeige wurde mithilfe von Match (mit .Index) aktualisiert, um einen Wert in einer Dimension eines zweidimensionalen Arrays zu finden:

Dim arr(1 To 10, 1 To 2)
Dim x

For x = 1 To 10
    arr(x, 1) = x
    arr(x, 2) = 11 - x
Next x

Debug.Print Application.Match(3, Application.Index(arr, 0, 1), 0)
Debug.Print Application.Match(3, Application.Index(arr, 0, 2), 0)

BEARBEITEN: Es lohnt sich zu illustrieren, was @ARich in den Kommentaren hervorgehoben hat - dass die Verwendung von Index() zum Schneiden eines Arrays eine schreckliche Leistung hat, wenn Sie es in einer Schleife ausführen.

Beim Testen (Code unten) ist der Index () - Ansatz fast 2000-fach langsamer als bei Verwendung einer geschachtelten Schleife.

Sub PerfTest()

    Const VAL_TO_FIND As String = "R1800:C8"
    Dim a(1 To 2000, 1 To 10)
    Dim r As Long, c As Long, t

    For r = 1 To 2000
        For c = 1 To 10
            a(r, c) = "R" & r & ":C" & c
        Next c
    Next r

    t = Timer
    Debug.Print FindLoop(a, VAL_TO_FIND), Timer - t
    ' >> 0.00781 sec

     t = Timer
    Debug.Print FindIndex(a, VAL_TO_FIND), Timer - t
    ' >> 14.18 sec

End Sub

Function FindLoop(arr, val) As Boolean
    Dim r As Long, c As Long
    For r = 1 To UBound(arr, 1)
    For c = 1 To UBound(arr, 2)
        If arr(r, c) = val Then
            FindLoop = True
            Exit Function
        End If
    Next c
    Next r
End Function

Function FindIndex(arr, val)
    Dim r As Long
    For r = 1 To UBound(arr, 1)
        If Not IsError(Application.Match(val, Application.Index(arr, r, 0), 0)) Then
            FindIndex = True
            Exit Function
        End If
    Next r
End Function
66
Tim Williams

reihe von Varianten:

    Public Function GetIndex(ByRef iaList() As Variant, ByVal value As Variant) As Long

    Dim i As Long

     For i = LBound(iaList) To UBound(iaList)
      If value = iaList(i) Then
       GetIndex = i
       Exit For
      End If
     Next i

    End Function

eine schnellste Version für Ganzzahlen (wie unten getestet)

    Public Function GetIndex(ByRef iaList() As Integer, ByVal value As Integer) As Integer
     Dim i As Integer

     For i = LBound(iaList) To UBound(iaList)
      If iaList(i) = value Then: GetIndex = i: Exit For:
     Next i

    End Function

' a snippet, replace myList and myValue to your varible names: (also have not tested)

mit einem Snippet können wir die Annahme testen, dass die Referenzübergabe als Argument etwas bedeutet. (die Antwort ist nein) Um es zu verwenden, ersetzen Sie myList und myValue durch Ihre Variablennamen

  Dim found As Integer, foundi As Integer ' put only once
  found = -1
  For foundi = LBound(myList) To UBound(myList):
   If myList(foundi) = myValue Then
    found = foundi: Exit For
   End If
  Next
  result = found

um den Punkt zu beweisen, habe ich einige Benchmarks gemacht 

hier sind die Ergebnisse:

---------------------------
Milliseconds
---------------------------
result0: 5 ' just empty loop

result1: 2702  ' function variant array

result2: 1498  ' function integer array

result3: 2511 ' snippet variant array

result4: 1508 ' snippet integer array

result5: 58493 ' Excel function Application.Match on variant array

result6: 136128 ' Excel function Application.Match on integer array
---------------------------
OK   
---------------------------

ein Modul:

Public Declare Function GetTickCount Lib "kernel32.dll" () As Long
#If VBA7 Then
    Public Declare PtrSafe Sub Sleep Lib "kernel32" (ByVal dwMilliseconds As LongPtr) 'For 64 Bit Systems
#Else
    Public Declare Sub Sleep Lib "kernel32" (ByVal dwMilliseconds As Long) 'For 32 Bit Systems
#End If

    Public Function GetIndex1(ByRef iaList() As Variant, ByVal value As Variant) As Long

    Dim i As Long

     For i = LBound(iaList) To UBound(iaList)
      If value = iaList(i) Then
       GetIndex = i
       Exit For
      End If
     Next i

    End Function


'maybe a faster variant for integers

    Public Function GetIndex2(ByRef iaList() As Integer, ByVal value As Integer) As Integer
     Dim i As Integer

     For i = LBound(iaList) To UBound(iaList)
      If iaList(i) = value Then: GetIndex = i: Exit For:
     Next i

    End Function

' a snippet, replace myList and myValue to your varible names: (also have not tested)



    Public Sub test1()
     Dim i As Integer

     For i = LBound(iaList) To UBound(iaList)
      If iaList(i) = value Then: GetIndex = i: Exit For:
     Next i

    End Sub


Sub testTimer()

Dim myList(500) As Variant, myValue As Variant
Dim myList2(500) As Integer, myValue2 As Integer
Dim n

For n = 1 To 500
myList(n) = n
Next

For n = 1 To 500
myList2(n) = n
Next

myValue = 100
myValue2 = 100


Dim oPM
Set oPM = New PerformanceMonitor
Dim result0 As Long
Dim result1 As Long
Dim result2 As Long
Dim result3 As Long
Dim result4 As Long
Dim result5 As Long
Dim result6 As Long

Dim t As Long

Dim a As Long

a = 0
Dim i
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000

Next
result0 = oPM.TimeElapsed() '  GetTickCount - t

a = 0

't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = GetIndex1(myList, myValue)
Next
result1 = oPM.TimeElapsed()
'result1 = GetTickCount - t


a = 0

't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = GetIndex2(myList2, myValue2)
Next
result2 = oPM.TimeElapsed()
'result2 = GetTickCount - t



a = 0

't = GetTickCount

oPM.StartCounter
Dim found As Integer, foundi As Integer ' put only once
For i = 1 To 1000000
found = -1
For foundi = LBound(myList) To UBound(myList):
 If myList(foundi) = myValue Then
  found = foundi: Exit For
 End If
Next
a = found
Next
result3 = oPM.TimeElapsed()
'result3 = GetTickCount - t



a = 0

't = GetTickCount

oPM.StartCounter
For i = 1 To 1000000
found = -1
For foundi = LBound(myList2) To UBound(myList2):
 If myList2(foundi) = myValue2 Then
  found = foundi: Exit For
 End If
Next
a = found
Next
result4 = oPM.TimeElapsed()
'result4 = GetTickCount - t


a = 0

't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = pos = Application.Match(myValue, myList, False)
Next
result5 = oPM.TimeElapsed()
'result5 = GetTickCount - t



a = 0

't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = pos = Application.Match(myValue2, myList2, False)
Next
result6 = oPM.TimeElapsed()
'result6 = GetTickCount - t


MsgBox "result0: " & result0 & vbCrLf & "result1: " & result1 & vbCrLf & "result2: " & result2 & vbCrLf & "result3: " & result3 & vbCrLf & "result4: " & result4 & vbCrLf & "result5: " & result5 & vbCrLf & "result6: " & result6, , "Milliseconds"
End Sub

eine Klasse mit dem Namen PerformanceMonitor

Option Explicit

Private Type LARGE_INTEGER
    lowpart As Long
    highpart As Long
End Type

Private Declare Function QueryPerformanceCounter Lib "kernel32" (lpPerformanceCount As LARGE_INTEGER) As Long
Private Declare Function QueryPerformanceFrequency Lib "kernel32" (lpFrequency As LARGE_INTEGER) As Long

Private m_CounterStart As LARGE_INTEGER
Private m_CounterEnd As LARGE_INTEGER
Private m_crFrequency As Double

Private Const TWO_32 = 4294967296# ' = 256# * 256# * 256# * 256#

Private Function LI2Double(LI As LARGE_INTEGER) As Double
Dim Low As Double
    Low = LI.lowpart
    If Low < 0 Then
        Low = Low + TWO_32
    End If
    LI2Double = LI.highpart * TWO_32 + Low
End Function

Private Sub Class_Initialize()
Dim PerfFrequency As LARGE_INTEGER
    QueryPerformanceFrequency PerfFrequency
    m_crFrequency = LI2Double(PerfFrequency)
End Sub

Public Sub StartCounter()
    QueryPerformanceCounter m_CounterStart
End Sub

Property Get TimeElapsed() As Double
Dim crStart As Double
Dim crStop As Double
    QueryPerformanceCounter m_CounterEnd
    crStart = LI2Double(m_CounterStart)
    crStop = LI2Double(m_CounterEnd)
    TimeElapsed = 1000# * (crStop - crStart) / m_crFrequency
End Property
2
Shimon Doodkin

Hier ist ein anderer Weg: 

Option Explicit

' Just a little test stub. 
Sub Tester()

    Dim pList(500) As Integer
    Dim i As Integer

    For i = 0 To UBound(pList)

        pList(i) = 500 - i

    Next i

    MsgBox "Value 18 is at array position " & FindInArray(pList, 18) & "."
    MsgBox "Value 217 is at array position " & FindInArray(pList, 217) & "."
    MsgBox "Value 1001 is at array position " & FindInArray(pList, 1001) & "."

End Sub

Function FindInArray(pList() As Integer, value As Integer)

    Dim i As Integer
    Dim FoundValueLocation As Integer

    FoundValueLocation = -1

    For i = 0 To UBound(pList)

        If pList(i) = value Then

            FoundValueLocation = i
            Exit For

        End If

    Next i

    FindInArray = FoundValueLocation

End Function
1
Paul McLain
'To return the position of an element within any-dimension array  
'Returns 0 if the element is not in the array, and -1 if there is an error  
Public Function posInArray(ByVal itemSearched As Variant, ByVal aArray As Variant) As Long  
Dim pos As Long, item As Variant  

posInArray = -1  
If IsArray(aArray) Then  
    If not IsEmpty(aArray) Then  
        pos = 1  
        For Each item In aArray  
            If itemSearched = item Then  
                posInArray = pos  
                Exit Function  
            End If  
            pos = pos + 1  
        Next item  
        posInArray = 0  
    End If  
End If

End Function
0
Guest

Die einzige (und wenn auch umständliche, aber dennoch zweckmäßige/relativ schnelle) Möglichkeit, dies zu tun, besteht darin, das beliebig dimensionale Array zu verketten und auf "1 Dimension" zu reduzieren, mit "/ [Spaltennummer] //\|" als Trennzeichen.

& Verwenden Sie für diese 1-d-Spalte eine einzelne Zellenergebnis-Lookupall-Makrofunktion. 

& dann Indexvergleich, um die Positionen herauszuziehen. (Verwendung mehrerer Suchtreffer)

Auf diese Weise erhalten Sie alle übereinstimmenden Vorkommen des gesuchten Elements/Strings im ursprünglichen Array mit beliebiger Dimension und deren Positionen. In einer Zelle.

Ich wünschte, ich könnte ein Makro/eine Funktion für diesen gesamten Prozess schreiben. Es würde mir mehr Aufregung ersparen. 

0
David Woolley

Suchst du danach?

public function GetIndex(byref iaList() as integer, byval iInteger as integer) as integer

dim i as integer

 for i=lbound(ialist) to ubound(ialist)
  if iInteger=ialist(i) then
   GetIndex=i
   exit for
  end if
 next i

end function
0
Jon49

Achten Sie darauf, ob das Array bei Null oder Eins beginnt. __ Wenn die Position 0 oder 1 von der Funktion zurückgegeben wird, stellen Sie sicher, dass dieselbe nicht mit True oder False von der Funktion zurückgegeben wird.

Function array_return_index(arr As Variant, val As Variant, Optional array_start_at_zero As Boolean = True) As Variant

Dim pos
pos = Application.Match(val, arr, False)

If Not IsError(pos) Then
    If array_start_at_zero = True Then
        pos = pos - 1
        'initializing array at 0
    End If
   array_return_index = pos
Else
   array_return_index = False
End If

End Function

Sub array_return_index_test()
Dim pos, arr, val

arr = Array(1, 2, 4, 5)
val = 1

'When array starts at zero
pos = array_return_index(arr, val)
If IsNumeric(pos) Then
MsgBox "Array starting at 0; Value found at : " & pos
Else
MsgBox "Not found"
End If

'When array starts at one
pos = array_return_index(arr, val, False)
If IsNumeric(pos) Then
MsgBox "Array starting at 1; Value found at : " & pos
Else
MsgBox "Not found"
End If



End Sub
0
luvlogic