Abrufen des Ortsnamens von Latitude & Longitude in iOS
Ich möchte den aktuellen Standortnamen nach Längen- und Breitengrad suchen.
Hier ist mein Code-Snippet, das ich ausprobiert habe, aber mein Protokoll zeigt an allen Stellen einen Nullwert, außer in placemark, placemark.ISOcountryCode und placemark.country
Ich möchte den Wert von placemark.locality und placemark.subLocality, aber es werden Nullwerte angezeigt.
- (void)viewWillAppear:(BOOL)animated
{
[super viewWillAppear:animated];
// this creates the CCLocationManager that will find your current location
locationManager = [[CLLocationManager alloc] init];
locationManager.delegate = self;
locationManager.desiredAccuracy = kCLLocationAccuracyNearestTenMeters;
[locationManager startUpdatingLocation];
}
// this delegate is called when the app successfully finds your current location
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder reverseGeocodeLocation:locationManager.location
completionHandler:^(NSArray *placemarks, NSError *error) {
NSLog(@"reverseGeocodeLocation:completionHandler: Completion Handler called!");
if (error){
NSLog(@"Geocode failed with error: %@", error);
return;
}
NSLog(@"placemarks=%@",[placemarks objectAtIndex:0]);
CLPlacemark *placemark = [placemarks objectAtIndex:0];
NSLog(@"placemark.ISOcountryCode =%@",placemark.ISOcountryCode);
NSLog(@"placemark.country =%@",placemark.country);
NSLog(@"placemark.postalCode =%@",placemark.postalCode);
NSLog(@"placemark.administrativeArea =%@",placemark.administrativeArea);
NSLog(@"placemark.locality =%@",placemark.locality);
NSLog(@"placemark.subLocality =%@",placemark.subLocality);
NSLog(@"placemark.subThoroughfare =%@",placemark.subThoroughfare);
}];
}
// this delegate method is called if an error occurs in locating your current location
- (void)locationManager:(CLLocationManager *)manager didFailWithError:(NSError *)error
{
NSLog(@"locationManager:%@ didFailWithError:%@", manager, error);
}
Danke im Voraus.
EDIT:
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
CLLocation *currentLocation = newLocation;
if (currentLocation != nil)
NSLog(@"longitude = %.8f\nlatitude = %.8f", currentLocation.coordinate.longitude,currentLocation.coordinate.latitude);
// stop updating location in order to save battery power
[locationManager stopUpdatingLocation];
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error)
{
NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0)
{
CLPlacemark *placemark = [placemarks lastObject];
// strAdd -> take bydefault value nil
NSString *strAdd = nil;
if ([placemark.subThoroughfare length] != 0)
strAdd = placemark.subThoroughfare;
if ([placemark.thoroughfare length] != 0)
{
// strAdd -> store value of current location
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark thoroughfare]];
else
{
// strAdd -> store only this value,which is not null
strAdd = placemark.thoroughfare;
}
}
if ([placemark.postalCode length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark postalCode]];
else
strAdd = placemark.postalCode;
}
if ([placemark.locality length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark locality]];
else
strAdd = placemark.locality;
}
if ([placemark.administrativeArea length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark administrativeArea]];
else
strAdd = placemark.administrativeArea;
}
if ([placemark.country length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark country]];
else
strAdd = placemark.country;
}
}
}];
}
Ich gebe Ihnen einen Ausschnitt, den ich zur Adressauflösung benutze. Ich füge auch Kommentar an notwendiger Stelle hinzu, um den Code für Sie zu verstehen. Abgesehen davon können Sie jederzeit Fragen aus dem Snippet stellen, wenn Sie etwas nicht verstehen.
Schreiben Sie das folgende Snippet in der didUpdateToLocation-Methode
NSLog(@"didUpdateToLocation: %@", newLocation);
CLLocation *currentLocation = newLocation;
if (currentLocation != nil)
NSLog(@"longitude = %.8f\nlatitude = %.8f", currentLocation.coordinate.longitude,currentLocation.coordinate.latitude);
// stop updating location in order to save battery power
[locationManager stopUpdatingLocation];
// Reverse Geocoding
NSLog(@"Resolving the Address");
// “reverseGeocodeLocation” method to translate the locate data into a human-readable address.
// The reason for using "completionHandler" ----
// Instead of using delegate to provide feedback, the CLGeocoder uses “block” to deal with the response. By using block, you do not need to write a separate method. Just provide the code inline to execute after the geocoding call completes.
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error)
{
NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0)
{
placemark = [placemarks lastObject];
// strAdd -> take bydefault value nil
NSString *strAdd = nil;
if ([placemark.subThoroughfare length] != 0)
strAdd = placemark.subThoroughfare;
if ([placemark.thoroughfare length] != 0)
{
// strAdd -> store value of current location
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark thoroughfare]];
else
{
// strAdd -> store only this value,which is not null
strAdd = placemark.thoroughfare;
}
}
if ([placemark.postalCode length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark postalCode]];
else
strAdd = placemark.postalCode;
}
if ([placemark.locality length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark locality]];
else
strAdd = placemark.locality;
}
if ([placemark.administrativeArea length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark administrativeArea]];
else
strAdd = placemark.administrativeArea;
}
if ([placemark.country length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark country]];
else
strAdd = placemark.country;
}
Wo strAdd die Adresse mittels Geolocation zurückgibt.
Viel Spaß beim Programmieren !!
Methode mit Abschlussblock:
typedef void(^addressCompletion)(NSString *);
-(void)getAddressFromLocation:(CLLocation *)location complationBlock:(addressCompletion)completionBlock
{
__block CLPlacemark* placemark;
__block NSString *address = nil;
CLGeocoder* geocoder = [CLGeocoder new];
[geocoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error)
{
if (error == nil && [placemarks count] > 0)
{
placemark = [placemarks lastObject];
address = [NSString stringWithFormat:@"%@, %@ %@", placemark.name, placemark.postalCode, placemark.locality];
completionBlock(address);
}
}];
}
So verwenden Sie es:
CLLocation* eventLocation = [[CLLocation alloc] initWithLatitude:_latitude longitude:_longitude];
[self getAddressFromLocation:eventLocation complationBlock:^(NSString * address) {
if(address) {
_address = address;
}
}];
Ich implementierte die Lösung von Niru in Swift 3 und poste hier, wenn jemand sie braucht:
let geocoder = CLGeocoder()
geocoder.reverseGeocodeLocation(self.location!) { (placemarksArray, error) in
if (placemarksArray?.count)! > 0 {
let placemark = placemarksArray?.first
let number = placemark!.subThoroughfare
let bairro = placemark!.subLocality
let street = placemark!.thoroughfare
self.addressLabel.text = "\(street!), \(number!) - \(bairro!)"
}
}
Verwenden Sie Google API für umgekehrtes Geotagging:
URL: http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224 ,-73.961452&sensor=true_or_false
Von: https://developers.google.com/maps/documentation/geocoding/
In Swift 4.1 und Xcode 9.4.1 ist dies eine meiner Lösungen. Hier verwende ich geocode API, um die vollständige Adresse zu erhalten. Mit dieser API kann ich auch die Dorfnamen bekommen.
Ich verwende reverseGeocodeLocation , aber es werden keine Dorfadressen oder Dorfnamen abgerufen, es kommt nur in der Nähe von Städtenamen ...
func getAddressForLatLng(latitude: String, longitude: String) { // Call this function
let url = NSURL(string: "https://maps.googleapis.com/maps/api/geocode/json?latlng=\(latitude),\(longitude)")//Here pass your latitude, longitude
print(url!)
let data = NSData(contentsOf: url! as URL)
if data != nil {
let json = try! JSONSerialization.jsonObject(with: data! as Data, options: JSONSerialization.ReadingOptions.allowFragments) as! NSDictionary
print(json)
let status = json["status"] as! String
if status == "OK" {
if let result = json["results"] as? NSArray {
if result.count > 0 {
if let addresss:NSDictionary = result[0] as? NSDictionary {
if let address = addresss["address_components"] as? NSArray {
var newaddress = ""
var number = ""
var street = ""
var city = ""
var state = ""
var Zip = ""
var country = ""
if(address.count > 1) {
number = (address.object(at: 0) as! NSDictionary)["short_name"] as! String
}
if(address.count > 2) {
street = (address.object(at: 1) as! NSDictionary)["short_name"] as! String
}
if(address.count > 3) {
city = (address.object(at: 2) as! NSDictionary)["short_name"] as! String
}
if(address.count > 4) {
state = (address.object(at: 4) as! NSDictionary)["short_name"] as! String
}
if(address.count > 6) {
Zip = (address.object(at: 6) as! NSDictionary)["short_name"] as! String
}
newaddress = "\(number) \(street), \(city), \(state) \(Zip)"
print(newaddress)
// OR
//This is second type to fetch pincode, country, state like this type of data
for i in 0..<address.count {
print(((address.object(at: i) as! NSDictionary)["types"] as! Array)[0])
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "postal_code" {
Zip = (address.object(at: i) as! NSDictionary)["short_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "country" {
country = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "administrative_area_level_1" {
state = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "administrative_area_level_2" {
district = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
}
}
}
}
}
}
}
}
Rufen Sie diese Funktion so auf
self.getAddressForLatLng(latitude: "\(self.lat!)", longitude: "\(self.lng!)")
Wenn der Speicherort, den Sie abrufen möchten, in dieser Liste aufgeführt ist, ist in Ihrem Code ein Fehler aufgetreten.
http://developer.Apple.com/library/ios/#technotes/tn2289/_index.html#//Apple_ref/doc/uid/DTS40011305
andernfalls hat CLGeoCoder keine Adressen in andere Länder.
Ich hatte das gleiche Problem, also habe ich es benutzt, um die Adresse zu bekommen. Gibt eine wirklich genaue Adresse.
http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224 ,-73.961452&sensor=true_or_false
Filtern Sie zunächst Standorte in didUpdateToLocation, um die Verwendung von zwischengespeicherten oder falschen Positionen für die Geocodierung zu verhindern
NSTimeInterval locationAge = -[newLocation.timestamp timeIntervalSinceNow];
if (abs(locationAge) > 5.0) return;
if (newLocation.horizontalAccuracy < 0) return;
Versuchen Sie auch, die Methode reverseGeoCoding von didUpdateToLocation zu entfernen
Sobald Sie latitude, longitude Werte für einen Ort haben, können Sie CLGeocoder Verwenden. Hier ist ein Tutorial , das Ihnen helfen kann.
verwenden Sie diese API zum Abrufen der Daten und übergeben Sie die Werte lat und long.